2(b-2)=5(b+1)-3

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Solution for 2(b-2)=5(b+1)-3 equation:


Simplifying
2(b + -2) = 5(b + 1) + -3

Reorder the terms:
2(-2 + b) = 5(b + 1) + -3
(-2 * 2 + b * 2) = 5(b + 1) + -3
(-4 + 2b) = 5(b + 1) + -3

Reorder the terms:
-4 + 2b = 5(1 + b) + -3
-4 + 2b = (1 * 5 + b * 5) + -3
-4 + 2b = (5 + 5b) + -3

Reorder the terms:
-4 + 2b = 5 + -3 + 5b

Combine like terms: 5 + -3 = 2
-4 + 2b = 2 + 5b

Solving
-4 + 2b = 2 + 5b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-5b' to each side of the equation.
-4 + 2b + -5b = 2 + 5b + -5b

Combine like terms: 2b + -5b = -3b
-4 + -3b = 2 + 5b + -5b

Combine like terms: 5b + -5b = 0
-4 + -3b = 2 + 0
-4 + -3b = 2

Add '4' to each side of the equation.
-4 + 4 + -3b = 2 + 4

Combine like terms: -4 + 4 = 0
0 + -3b = 2 + 4
-3b = 2 + 4

Combine like terms: 2 + 4 = 6
-3b = 6

Divide each side by '-3'.
b = -2

Simplifying
b = -2

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