2(b-23)+3(b-4)=27

Solution for 2(b-23)+3(b-4)=27 equation:

Simplifying
2(b + -23) + 3(b + -4) = 27

Reorder the terms:
2(-23 + b) + 3(b + -4) = 27
(-23 * 2 + b * 2) + 3(b + -4) = 27
(-46 + 2b) + 3(b + -4) = 27

Reorder the terms:
-46 + 2b + 3(-4 + b) = 27
-46 + 2b + (-4 * 3 + b * 3) = 27
-46 + 2b + (-12 + 3b) = 27

Reorder the terms:
-46 + -12 + 2b + 3b = 27

Combine like terms: -46 + -12 = -58
-58 + 2b + 3b = 27

Combine like terms: 2b + 3b = 5b
-58 + 5b = 27

Solving
-58 + 5b = 27

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '58' to each side of the equation.
-58 + 58 + 5b = 27 + 58

Combine like terms: -58 + 58 = 0
0 + 5b = 27 + 58
5b = 27 + 58

Combine like terms: 27 + 58 = 85
5b = 85

Divide each side by '5'.
b = 17

Simplifying
b = 17