2(b-3)+1=11-(b+1)

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Solution for 2(b-3)+1=11-(b+1) equation:


Simplifying
2(b + -3) + 1 = 11 + -1(b + 1)

Reorder the terms:
2(-3 + b) + 1 = 11 + -1(b + 1)
(-3 * 2 + b * 2) + 1 = 11 + -1(b + 1)
(-6 + 2b) + 1 = 11 + -1(b + 1)

Reorder the terms:
-6 + 1 + 2b = 11 + -1(b + 1)

Combine like terms: -6 + 1 = -5
-5 + 2b = 11 + -1(b + 1)

Reorder the terms:
-5 + 2b = 11 + -1(1 + b)
-5 + 2b = 11 + (1 * -1 + b * -1)
-5 + 2b = 11 + (-1 + -1b)

Combine like terms: 11 + -1 = 10
-5 + 2b = 10 + -1b

Solving
-5 + 2b = 10 + -1b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add 'b' to each side of the equation.
-5 + 2b + b = 10 + -1b + b

Combine like terms: 2b + b = 3b
-5 + 3b = 10 + -1b + b

Combine like terms: -1b + b = 0
-5 + 3b = 10 + 0
-5 + 3b = 10

Add '5' to each side of the equation.
-5 + 5 + 3b = 10 + 5

Combine like terms: -5 + 5 = 0
0 + 3b = 10 + 5
3b = 10 + 5

Combine like terms: 10 + 5 = 15
3b = 15

Divide each side by '3'.
b = 5

Simplifying
b = 5

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