2(b-3)+3b=-16

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Solution for 2(b-3)+3b=-16 equation: 



2(b-3)+3b=-16

We move all terms to the left:

2(b-3)+3b-(-16)=0

We add all the numbers together, and all the variables

3b+2(b-3)+16=0

We multiply parentheses

3b+2b-6+16=0

We add all the numbers together, and all the variables

5b+10=0

We move all terms containing b to the left, all other terms to the right

5b=-10

b=-10/5

b=-2

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