2(b-3)+5=(b-1)

Solution for 2(b-3)+5=(b-1) equation:

Simplifying
2(b + -3) + 5 = (b + -1)

Reorder the terms:
2(-3 + b) + 5 = (b + -1)
(-3 * 2 + b * 2) + 5 = (b + -1)
(-6 + 2b) + 5 = (b + -1)

Reorder the terms:
-6 + 5 + 2b = (b + -1)

Combine like terms: -6 + 5 = -1
-1 + 2b = (b + -1)

Reorder the terms:
-1 + 2b = (-1 + b)

Remove parenthesis around (-1 + b)
-1 + 2b = -1 + b

Add '1' to each side of the equation.
-1 + 1 + 2b = -1 + 1 + b

Combine like terms: -1 + 1 = 0
0 + 2b = -1 + 1 + b
2b = -1 + 1 + b

Combine like terms: -1 + 1 = 0
2b = 0 + b
2b = b

Solving
2b = b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-1b' to each side of the equation.
2b + -1b = b + -1b

Combine like terms: 2b + -1b = 1b
1b = b + -1b

Combine like terms: b + -1b = 0
1b = 0

Divide each side by '1'.
b = 0

Simplifying
b = 0