2(b-3)+5=3(b-1)

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Solution for 2(b-3)+5=3(b-1) equation:


Simplifying
2(b + -3) + 5 = 3(b + -1)

Reorder the terms:
2(-3 + b) + 5 = 3(b + -1)
(-3 * 2 + b * 2) + 5 = 3(b + -1)
(-6 + 2b) + 5 = 3(b + -1)

Reorder the terms:
-6 + 5 + 2b = 3(b + -1)

Combine like terms: -6 + 5 = -1
-1 + 2b = 3(b + -1)

Reorder the terms:
-1 + 2b = 3(-1 + b)
-1 + 2b = (-1 * 3 + b * 3)
-1 + 2b = (-3 + 3b)

Solving
-1 + 2b = -3 + 3b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-3b' to each side of the equation.
-1 + 2b + -3b = -3 + 3b + -3b

Combine like terms: 2b + -3b = -1b
-1 + -1b = -3 + 3b + -3b

Combine like terms: 3b + -3b = 0
-1 + -1b = -3 + 0
-1 + -1b = -3

Add '1' to each side of the equation.
-1 + 1 + -1b = -3 + 1

Combine like terms: -1 + 1 = 0
0 + -1b = -3 + 1
-1b = -3 + 1

Combine like terms: -3 + 1 = -2
-1b = -2

Divide each side by '-1'.
b = 2

Simplifying
b = 2

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