2(b-3)-2(3b-5)=4(3-b)

Solution for 2(b-3)-2(3b-5)=4(3-b) equation:

Simplifying
2(b + -3) + -2(3b + -5) = 4(3 + -1b)

Reorder the terms:
2(-3 + b) + -2(3b + -5) = 4(3 + -1b)
(-3 * 2 + b * 2) + -2(3b + -5) = 4(3 + -1b)
(-6 + 2b) + -2(3b + -5) = 4(3 + -1b)

Reorder the terms:
-6 + 2b + -2(-5 + 3b) = 4(3 + -1b)
-6 + 2b + (-5 * -2 + 3b * -2) = 4(3 + -1b)
-6 + 2b + (10 + -6b) = 4(3 + -1b)

Reorder the terms:
-6 + 10 + 2b + -6b = 4(3 + -1b)

Combine like terms: -6 + 10 = 4
4 + 2b + -6b = 4(3 + -1b)

Combine like terms: 2b + -6b = -4b
4 + -4b = 4(3 + -1b)
4 + -4b = (3 * 4 + -1b * 4)
4 + -4b = (12 + -4b)

Add '4b' to each side of the equation.
4 + -4b + 4b = 12 + -4b + 4b

Combine like terms: -4b + 4b = 0
4 + 0 = 12 + -4b + 4b
4 = 12 + -4b + 4b

Combine like terms: -4b + 4b = 0
4 = 12 + 0
4 = 12

Solving
4 = 12

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.