2(b-3)=4(b-4)-10

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Solution for 2(b-3)=4(b-4)-10 equation:


Simplifying
2(b + -3) = 4(b + -4) + -10

Reorder the terms:
2(-3 + b) = 4(b + -4) + -10
(-3 * 2 + b * 2) = 4(b + -4) + -10
(-6 + 2b) = 4(b + -4) + -10

Reorder the terms:
-6 + 2b = 4(-4 + b) + -10
-6 + 2b = (-4 * 4 + b * 4) + -10
-6 + 2b = (-16 + 4b) + -10

Reorder the terms:
-6 + 2b = -16 + -10 + 4b

Combine like terms: -16 + -10 = -26
-6 + 2b = -26 + 4b

Solving
-6 + 2b = -26 + 4b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-4b' to each side of the equation.
-6 + 2b + -4b = -26 + 4b + -4b

Combine like terms: 2b + -4b = -2b
-6 + -2b = -26 + 4b + -4b

Combine like terms: 4b + -4b = 0
-6 + -2b = -26 + 0
-6 + -2b = -26

Add '6' to each side of the equation.
-6 + 6 + -2b = -26 + 6

Combine like terms: -6 + 6 = 0
0 + -2b = -26 + 6
-2b = -26 + 6

Combine like terms: -26 + 6 = -20
-2b = -20

Divide each side by '-2'.
b = 10

Simplifying
b = 10

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