2(b-4)+15=13

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Solution for 2(b-4)+15=13 equation: 



2(b-4)+15=13

We move all terms to the left:

2(b-4)+15-(13)=0

We add all the numbers together, and all the variables

2(b-4)+2=0

We multiply parentheses

2b-8+2=0

We add all the numbers together, and all the variables

2b-6=0

We move all terms containing b to the left, all other terms to the right

2b=6

b=6/2

b=3

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