2(b-4)+8=1/2(6b+20)

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Solution for 2(b-4)+8=1/2(6b+20) equation: 



2(b-4)+8=1/2(6b+20)

We move all terms to the left:

2(b-4)+8-(1/2(6b+20))=0



Domain of the equation: 2(6b+20))!=0

b∈R



We multiply parentheses

2b-(1/2(6b+20))-8+8=0

We multiply all the terms by the denominator


2b*2(6b+20))-(1-8*2(6b+20))+8*2(6b+20))=0

We add all the numbers together, and all the variables

2b*2(6b+20))-(1-8*2(6b+20))+8*2(6b=0

Wy multiply elements

4b^2(6-32b^2(6=0

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