2(b-4)-4=3(b-8)

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Solution for 2(b-4)-4=3(b-8) equation:


Simplifying
2(b + -4) + -4 = 3(b + -8)

Reorder the terms:
2(-4 + b) + -4 = 3(b + -8)
(-4 * 2 + b * 2) + -4 = 3(b + -8)
(-8 + 2b) + -4 = 3(b + -8)

Reorder the terms:
-8 + -4 + 2b = 3(b + -8)

Combine like terms: -8 + -4 = -12
-12 + 2b = 3(b + -8)

Reorder the terms:
-12 + 2b = 3(-8 + b)
-12 + 2b = (-8 * 3 + b * 3)
-12 + 2b = (-24 + 3b)

Solving
-12 + 2b = -24 + 3b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-3b' to each side of the equation.
-12 + 2b + -3b = -24 + 3b + -3b

Combine like terms: 2b + -3b = -1b
-12 + -1b = -24 + 3b + -3b

Combine like terms: 3b + -3b = 0
-12 + -1b = -24 + 0
-12 + -1b = -24

Add '12' to each side of the equation.
-12 + 12 + -1b = -24 + 12

Combine like terms: -12 + 12 = 0
0 + -1b = -24 + 12
-1b = -24 + 12

Combine like terms: -24 + 12 = -12
-1b = -12

Divide each side by '-1'.
b = 12

Simplifying
b = 12

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