2(b-4)=-4b+2(4-b)

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Solution for 2(b-4)=-4b+2(4-b) equation: 



2(b-4)=-4b+2(4-b)

We move all terms to the left:

2(b-4)-(-4b+2(4-b))=0

We add all the numbers together, and all the variables

2(b-4)-(-4b+2(-1b+4))=0

We multiply parentheses

2b-(-4b+2(-1b+4))-8=0



We calculate terms in parentheses: -(-4b+2(-1b+4)), so:

-4b+2(-1b+4)

We multiply parentheses

-4b-2b+8

We add all the numbers together, and all the variables

-6b+8

Back to the equation:

-(-6b+8)



We get rid of parentheses

2b+6b-8-8=0

We add all the numbers together, and all the variables

8b-16=0

We move all terms containing b to the left, all other terms to the right

8b=16

b=16/8

b=2

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