2(b-4)=3(b-5)

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Solution for 2(b-4)=3(b-5) equation:


Simplifying
2(b + -4) = 3(b + -5)

Reorder the terms:
2(-4 + b) = 3(b + -5)
(-4 * 2 + b * 2) = 3(b + -5)
(-8 + 2b) = 3(b + -5)

Reorder the terms:
-8 + 2b = 3(-5 + b)
-8 + 2b = (-5 * 3 + b * 3)
-8 + 2b = (-15 + 3b)

Solving
-8 + 2b = -15 + 3b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-3b' to each side of the equation.
-8 + 2b + -3b = -15 + 3b + -3b

Combine like terms: 2b + -3b = -1b
-8 + -1b = -15 + 3b + -3b

Combine like terms: 3b + -3b = 0
-8 + -1b = -15 + 0
-8 + -1b = -15

Add '8' to each side of the equation.
-8 + 8 + -1b = -15 + 8

Combine like terms: -8 + 8 = 0
0 + -1b = -15 + 8
-1b = -15 + 8

Combine like terms: -15 + 8 = -7
-1b = -7

Divide each side by '-1'.
b = 7

Simplifying
b = 7

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