2(b-4)=5(b+2)-9

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Solution for 2(b-4)=5(b+2)-9 equation:


Simplifying
2(b + -4) = 5(b + 2) + -9

Reorder the terms:
2(-4 + b) = 5(b + 2) + -9
(-4 * 2 + b * 2) = 5(b + 2) + -9
(-8 + 2b) = 5(b + 2) + -9

Reorder the terms:
-8 + 2b = 5(2 + b) + -9
-8 + 2b = (2 * 5 + b * 5) + -9
-8 + 2b = (10 + 5b) + -9

Reorder the terms:
-8 + 2b = 10 + -9 + 5b

Combine like terms: 10 + -9 = 1
-8 + 2b = 1 + 5b

Solving
-8 + 2b = 1 + 5b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-5b' to each side of the equation.
-8 + 2b + -5b = 1 + 5b + -5b

Combine like terms: 2b + -5b = -3b
-8 + -3b = 1 + 5b + -5b

Combine like terms: 5b + -5b = 0
-8 + -3b = 1 + 0
-8 + -3b = 1

Add '8' to each side of the equation.
-8 + 8 + -3b = 1 + 8

Combine like terms: -8 + 8 = 0
0 + -3b = 1 + 8
-3b = 1 + 8

Combine like terms: 1 + 8 = 9
-3b = 9

Divide each side by '-3'.
b = -3

Simplifying
b = -3

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