2(b-4)=8b-11(28)

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Solution for 2(b-4)=8b-11(28) equation:


Simplifying
2(b + -4) = 8b + -11(28)

Reorder the terms:
2(-4 + b) = 8b + -11(28)
(-4 * 2 + b * 2) = 8b + -11(28)
(-8 + 2b) = 8b + -11(28)

Multiply -11 * 28
-8 + 2b = 8b + -308

Reorder the terms:
-8 + 2b = -308 + 8b

Solving
-8 + 2b = -308 + 8b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-8b' to each side of the equation.
-8 + 2b + -8b = -308 + 8b + -8b

Combine like terms: 2b + -8b = -6b
-8 + -6b = -308 + 8b + -8b

Combine like terms: 8b + -8b = 0
-8 + -6b = -308 + 0
-8 + -6b = -308

Add '8' to each side of the equation.
-8 + 8 + -6b = -308 + 8

Combine like terms: -8 + 8 = 0
0 + -6b = -308 + 8
-6b = -308 + 8

Combine like terms: -308 + 8 = -300
-6b = -300

Divide each side by '-6'.
b = 50

Simplifying
b = 50

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