2(b-5)+3(b-2)=8+7(b-4)

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Solution for 2(b-5)+3(b-2)=8+7(b-4) equation:


2(b-5)+3(b-2)=8+7(b-4)

We simplify the equation to the form, which is simple to understand 
2(b-5)+3(b-2)=8+7(b-4)

Reorder the terms in parentheses
+(+2b-10)+3*(b-2)=8+7*(b-4)

Remove unnecessary parentheses
+2b-10+3+*(+b-2+)=+8+7+*(+b-4+)

Reorder the terms in parentheses
+2b-10+(+3b-6)=8+7*(b-4)

Remove unnecessary parentheses
+2b-10+3b-6=+8+7+*(+b-4+)

Reorder the terms in parentheses
+2b-10+3b-6=8+(+7b-28)

Remove unnecessary parentheses
+2b-10+3b-6=+8+7b-28

We move all terms containing b to the left and all other terms to the right. 
+2b+3b-7b=+8-28+10+6

We simplify left and right side of the equation. 
-2b=-4

We divide both sides of the equation by -2 to get b. 
b=2

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