2(b-5)+3(b-2)=8=7(b-4)

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Solution for 2(b-5)+3(b-2)=8=7(b-4) equation: 



2(b-5)+3(b-2)=8=7(b-4)

We move all terms to the left:

2(b-5)+3(b-2)-(8)=0

We multiply parentheses

2b+3b-10-6-8=0

We add all the numbers together, and all the variables

5b-24=0

We move all terms containing b to the left, all other terms to the right

5b=24

b=24/5

b=4+4/5

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