2(b-5)+4b=3-(b-1)

Solution for 2(b-5)+4b=3-(b-1) equation:

Simplifying
2(b + -5) + 4b = 3 + -1(b + -1)

Reorder the terms:
2(-5 + b) + 4b = 3 + -1(b + -1)
(-5 * 2 + b * 2) + 4b = 3 + -1(b + -1)
(-10 + 2b) + 4b = 3 + -1(b + -1)

Combine like terms: 2b + 4b = 6b
-10 + 6b = 3 + -1(b + -1)

Reorder the terms:
-10 + 6b = 3 + -1(-1 + b)
-10 + 6b = 3 + (-1 * -1 + b * -1)
-10 + 6b = 3 + (1 + -1b)

Combine like terms: 3 + 1 = 4
-10 + 6b = 4 + -1b

Solving
-10 + 6b = 4 + -1b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add 'b' to each side of the equation.
-10 + 6b + b = 4 + -1b + b

Combine like terms: 6b + b = 7b
-10 + 7b = 4 + -1b + b

Combine like terms: -1b + b = 0
-10 + 7b = 4 + 0
-10 + 7b = 4

Add '10' to each side of the equation.
-10 + 10 + 7b = 4 + 10

Combine like terms: -10 + 10 = 0
0 + 7b = 4 + 10
7b = 4 + 10

Combine like terms: 4 + 10 = 14
7b = 14

Divide each side by '7'.
b = 2

Simplifying
b = 2