2(b-5)-3(5b+8)=5(b-2)+17

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Solution for 2(b-5)-3(5b+8)=5(b-2)+17 equation: 



2(b-5)-3(5b+8)=5(b-2)+17

We move all terms to the left:

2(b-5)-3(5b+8)-(5(b-2)+17)=0

We multiply parentheses

2b-15b-(5(b-2)+17)-10-24=0



We calculate terms in parentheses: -(5(b-2)+17), so:

5(b-2)+17

We multiply parentheses

5b-10+17

We add all the numbers together, and all the variables

5b+7

Back to the equation:

-(5b+7)



We add all the numbers together, and all the variables

-13b-(5b+7)-34=0

We get rid of parentheses

-13b-5b-7-34=0

We add all the numbers together, and all the variables

-18b-41=0

We move all terms containing b to the left, all other terms to the right

-18b=41

b=41/-18

b=-2+5/18

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