2(b-5)=2b-7-3

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Solution for 2(b-5)=2b-7-3 equation:


Simplifying
2(b + -5) = 2b + -7 + -3

Reorder the terms:
2(-5 + b) = 2b + -7 + -3
(-5 * 2 + b * 2) = 2b + -7 + -3
(-10 + 2b) = 2b + -7 + -3

Reorder the terms:
-10 + 2b = -7 + -3 + 2b

Combine like terms: -7 + -3 = -10
-10 + 2b = -10 + 2b

Add '10' to each side of the equation.
-10 + 10 + 2b = -10 + 10 + 2b

Combine like terms: -10 + 10 = 0
0 + 2b = -10 + 10 + 2b
2b = -10 + 10 + 2b

Combine like terms: -10 + 10 = 0
2b = 0 + 2b
2b = 2b

Add '-2b' to each side of the equation.
2b + -2b = 2b + -2b

Combine like terms: 2b + -2b = 0
0 = 2b + -2b

Combine like terms: 2b + -2b = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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