2(b-5)=4(b-7)+12

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Solution for 2(b-5)=4(b-7)+12 equation: 



2(b-5)=4(b-7)+12

We move all terms to the left:

2(b-5)-(4(b-7)+12)=0

We multiply parentheses

2b-(4(b-7)+12)-10=0



We calculate terms in parentheses: -(4(b-7)+12), so:

4(b-7)+12

We multiply parentheses

4b-28+12

We add all the numbers together, and all the variables

4b-16

Back to the equation:

-(4b-16)



We get rid of parentheses

2b-4b+16-10=0

We add all the numbers together, and all the variables

-2b+6=0

We move all terms containing b to the left, all other terms to the right

-2b=-6

b=-6/-2

b=+3

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