2(b-5)=5(b+5)-17

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Solution for 2(b-5)=5(b+5)-17 equation:


Simplifying
2(b + -5) = 5(b + 5) + -17

Reorder the terms:
2(-5 + b) = 5(b + 5) + -17
(-5 * 2 + b * 2) = 5(b + 5) + -17
(-10 + 2b) = 5(b + 5) + -17

Reorder the terms:
-10 + 2b = 5(5 + b) + -17
-10 + 2b = (5 * 5 + b * 5) + -17
-10 + 2b = (25 + 5b) + -17

Reorder the terms:
-10 + 2b = 25 + -17 + 5b

Combine like terms: 25 + -17 = 8
-10 + 2b = 8 + 5b

Solving
-10 + 2b = 8 + 5b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-5b' to each side of the equation.
-10 + 2b + -5b = 8 + 5b + -5b

Combine like terms: 2b + -5b = -3b
-10 + -3b = 8 + 5b + -5b

Combine like terms: 5b + -5b = 0
-10 + -3b = 8 + 0
-10 + -3b = 8

Add '10' to each side of the equation.
-10 + 10 + -3b = 8 + 10

Combine like terms: -10 + 10 = 0
0 + -3b = 8 + 10
-3b = 8 + 10

Combine like terms: 8 + 10 = 18
-3b = 18

Divide each side by '-3'.
b = -6

Simplifying
b = -6

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