2(b-6)=9(b+12)

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Solution for 2(b-6)=9(b+12) equation:



2(b-6)=9(b+12)
We move all terms to the left:
2(b-6)-(9(b+12))=0
We multiply parentheses
2b-(9(b+12))-12=0
We calculate terms in parentheses: -(9(b+12)), so:
9(b+12)
We multiply parentheses
9b+108
Back to the equation:
-(9b+108)
We get rid of parentheses
2b-9b-108-12=0
We add all the numbers together, and all the variables
-7b-120=0
We move all terms containing b to the left, all other terms to the right
-7b=120
b=120/-7
b=-17+1/7

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