2(b-6)=9(b+12)

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Solution for 2(b-6)=9(b+12) equation: 



2(b-6)=9(b+12)

We move all terms to the left:

2(b-6)-(9(b+12))=0

We multiply parentheses

2b-(9(b+12))-12=0



We calculate terms in parentheses: -(9(b+12)), so:

9(b+12)

We multiply parentheses

9b+108

Back to the equation:

-(9b+108)



We get rid of parentheses

2b-9b-108-12=0

We add all the numbers together, and all the variables

-7b-120=0

We move all terms containing b to the left, all other terms to the right

-7b=120

b=120/-7

b=-17+1/7

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