2(b-8)+7=5(b+2)-3b-19

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Solution for 2(b-8)+7=5(b+2)-3b-19 equation:


Simplifying
2(b + -8) + 7 = 5(b + 2) + -3b + -19

Reorder the terms:
2(-8 + b) + 7 = 5(b + 2) + -3b + -19
(-8 * 2 + b * 2) + 7 = 5(b + 2) + -3b + -19
(-16 + 2b) + 7 = 5(b + 2) + -3b + -19

Reorder the terms:
-16 + 7 + 2b = 5(b + 2) + -3b + -19

Combine like terms: -16 + 7 = -9
-9 + 2b = 5(b + 2) + -3b + -19

Reorder the terms:
-9 + 2b = 5(2 + b) + -3b + -19
-9 + 2b = (2 * 5 + b * 5) + -3b + -19
-9 + 2b = (10 + 5b) + -3b + -19

Reorder the terms:
-9 + 2b = 10 + -19 + 5b + -3b

Combine like terms: 10 + -19 = -9
-9 + 2b = -9 + 5b + -3b

Combine like terms: 5b + -3b = 2b
-9 + 2b = -9 + 2b

Add '9' to each side of the equation.
-9 + 9 + 2b = -9 + 9 + 2b

Combine like terms: -9 + 9 = 0
0 + 2b = -9 + 9 + 2b
2b = -9 + 9 + 2b

Combine like terms: -9 + 9 = 0
2b = 0 + 2b
2b = 2b

Add '-2b' to each side of the equation.
2b + -2b = 2b + -2b

Combine like terms: 2b + -2b = 0
0 = 2b + -2b

Combine like terms: 2b + -2b = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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