2(b-8)+8=8b-3

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Solution for 2(b-8)+8=8b-3 equation: 



2(b-8)+8=8b-3

We move all terms to the left:

2(b-8)+8-(8b-3)=0

We multiply parentheses

2b-(8b-3)-16+8=0

We get rid of parentheses

2b-8b+3-16+8=0

We add all the numbers together, and all the variables

-6b-5=0

We move all terms containing b to the left, all other terms to the right

-6b=5

b=5/-6

b=-5/6

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