2(b-8)+b=34-7b

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Solution for 2(b-8)+b=34-7b equation: 



2(b-8)+b=34-7b

We move all terms to the left:

2(b-8)+b-(34-7b)=0

We add all the numbers together, and all the variables

2(b-8)+b-(-7b+34)=0

We add all the numbers together, and all the variables

b+2(b-8)-(-7b+34)=0

We multiply parentheses

b+2b-(-7b+34)-16=0

We get rid of parentheses

b+2b+7b-34-16=0

We add all the numbers together, and all the variables

10b-50=0

We move all terms containing b to the left, all other terms to the right

10b=50

b=50/10

b=5

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