2(c+1)-3c+4=-c+5-15

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Solution for 2(c+1)-3c+4=-c+5-15 equation: 


Simplifying
2(c + 1) + -3c + 4 = -1c + 5 + -15

Reorder the terms:
2(1 + c) + -3c + 4 = -1c + 5 + -15
(1 * 2 + c * 2) + -3c + 4 = -1c + 5 + -15
(2 + 2c) + -3c + 4 = -1c + 5 + -15

Reorder the terms:
2 + 4 + 2c + -3c = -1c + 5 + -15

Combine like terms: 2 + 4 = 6
6 + 2c + -3c = -1c + 5 + -15

Combine like terms: 2c + -3c = -1c
6 + -1c = -1c + 5 + -15

Reorder the terms:
6 + -1c = 5 + -15 + -1c

Combine like terms: 5 + -15 = -10
6 + -1c = -10 + -1c

Add 'c' to each side of the equation.
6 + -1c + c = -10 + -1c + c

Combine like terms: -1c + c = 0
6 + 0 = -10 + -1c + c
6 = -10 + -1c + c

Combine like terms: -1c + c = 0
6 = -10 + 0
6 = -10

Solving
6 = -10

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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