2(c+1)c=4

Solution for 2(c+1)c=4 equation:

Simplifying
2(c + 1) * c = 4

Reorder the terms:
2(1 + c) * c = 4

Reorder the terms for easier multiplication:
2c(1 + c) = 4
(1 * 2c + c * 2c) = 4
(2c + 2c2) = 4

Solving
2c + 2c2 = 4

Solving for variable 'c'.

Reorder the terms:
-4 + 2c + 2c2 = 4 + -4

Combine like terms: 4 + -4 = 0
-4 + 2c + 2c2 = 0

Factor out the Greatest Common Factor (GCF), '2'.
2(-2 + c + c2) = 0

Factor a trinomial.
2((-2 + -1c)(1 + -1c)) = 0

Ignore the factor 2.
Subproblem 1
Set the factor '(-2 + -1c)' equal to zero and attempt to solve:

Simplifying
-2 + -1c = 0

Solving
-2 + -1c = 0

Move all terms containing c to the left, all other terms to the right.

Add '2' to each side of the equation.
-2 + 2 + -1c = 0 + 2

Combine like terms: -2 + 2 = 0
0 + -1c = 0 + 2
-1c = 0 + 2

Combine like terms: 0 + 2 = 2
-1c = 2

Divide each side by '-1'.
c = -2

Simplifying
c = -2
Subproblem 2
Set the factor '(1 + -1c)' equal to zero and attempt to solve:

Simplifying
1 + -1c = 0

Solving
1 + -1c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -1c = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -1c = 0 + -1
-1c = 0 + -1

Combine like terms: 0 + -1 = -1
-1c = -1

Divide each side by '-1'.
c = 1

Simplifying
c = 1
Solution
c = {-2, 1}