2(c+10)+12=4c-3

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Solution for 2(c+10)+12=4c-3 equation: 



2(c+10)+12=4c-3

We move all terms to the left:

2(c+10)+12-(4c-3)=0

We multiply parentheses

2c-(4c-3)+20+12=0

We get rid of parentheses

2c-4c+3+20+12=0

We add all the numbers together, and all the variables

-2c+35=0

We move all terms containing c to the left, all other terms to the right

-2c=-35

c=-35/-2

c=17+1/2

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