2(c+10)+3c+12=

Solution for 2(c+10)+3c+12= equation:

Simplifying
2(c + 10) + 3c + 12 = 0

Reorder the terms:
2(10 + c) + 3c + 12 = 0
(10 * 2 + c * 2) + 3c + 12 = 0
(20 + 2c) + 3c + 12 = 0

Reorder the terms:
20 + 12 + 2c + 3c = 0

Combine like terms: 20 + 12 = 32
32 + 2c + 3c = 0

Combine like terms: 2c + 3c = 5c
32 + 5c = 0

Solving
32 + 5c = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-32' to each side of the equation.
32 + -32 + 5c = 0 + -32

Combine like terms: 32 + -32 = 0
0 + 5c = 0 + -32
5c = 0 + -32

Combine like terms: 0 + -32 = -32
5c = -32

Divide each side by '5'.
c = -6.4

Simplifying
c = -6.4