2(c+2)+3c=6-3(4)

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Solution for 2(c+2)+3c=6-3(4) equation: 



2(c+2)+3c=6-3(4)

We move all terms to the left:

2(c+2)+3c-(6-3(4))=0

We add all the numbers together, and all the variables

2(c+2)+3c-(-28)=0

We add all the numbers together, and all the variables

3c+2(c+2)+28=0

We multiply parentheses

3c+2c+4+28=0

We add all the numbers together, and all the variables

5c+32=0

We move all terms containing c to the left, all other terms to the right

5c=-32

c=-32/5

c=-6+2/5

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