2(c+2)+4(c-1)=

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Solution for 2(c+2)+4(c-1)= equation:


Simplifying
2(c + 2) + 4(c + -1) = 0

Reorder the terms:
2(2 + c) + 4(c + -1) = 0
(2 * 2 + c * 2) + 4(c + -1) = 0
(4 + 2c) + 4(c + -1) = 0

Reorder the terms:
4 + 2c + 4(-1 + c) = 0
4 + 2c + (-1 * 4 + c * 4) = 0
4 + 2c + (-4 + 4c) = 0

Reorder the terms:
4 + -4 + 2c + 4c = 0

Combine like terms: 4 + -4 = 0
0 + 2c + 4c = 0
2c + 4c = 0

Combine like terms: 2c + 4c = 6c
6c = 0

Solving
6c = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Divide each side by '6'.
c = 0

Simplifying
c = 0

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