2(c+2)=4(c-2)

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Solution for 2(c+2)=4(c-2) equation: 



2(c+2)=4(c-2)

We move all terms to the left:

2(c+2)-(4(c-2))=0

We multiply parentheses

2c-(4(c-2))+4=0



We calculate terms in parentheses: -(4(c-2)), so:

4(c-2)

We multiply parentheses

4c-8

Back to the equation:

-(4c-8)



We get rid of parentheses

2c-4c+8+4=0

We add all the numbers together, and all the variables

-2c+12=0

We move all terms containing c to the left, all other terms to the right

-2c=-12

c=-12/-2

c=+6

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