2(c+2)=5(c+1)-7

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Solution for 2(c+2)=5(c+1)-7 equation:


Simplifying
2(c + 2) = 5(c + 1) + -7

Reorder the terms:
2(2 + c) = 5(c + 1) + -7
(2 * 2 + c * 2) = 5(c + 1) + -7
(4 + 2c) = 5(c + 1) + -7

Reorder the terms:
4 + 2c = 5(1 + c) + -7
4 + 2c = (1 * 5 + c * 5) + -7
4 + 2c = (5 + 5c) + -7

Reorder the terms:
4 + 2c = 5 + -7 + 5c

Combine like terms: 5 + -7 = -2
4 + 2c = -2 + 5c

Solving
4 + 2c = -2 + 5c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-5c' to each side of the equation.
4 + 2c + -5c = -2 + 5c + -5c

Combine like terms: 2c + -5c = -3c
4 + -3c = -2 + 5c + -5c

Combine like terms: 5c + -5c = 0
4 + -3c = -2 + 0
4 + -3c = -2

Add '-4' to each side of the equation.
4 + -4 + -3c = -2 + -4

Combine like terms: 4 + -4 = 0
0 + -3c = -2 + -4
-3c = -2 + -4

Combine like terms: -2 + -4 = -6
-3c = -6

Divide each side by '-3'.
c = 2

Simplifying
c = 2

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