2(c+2)=5(x+1)-7

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Solution for 2(c+2)=5(x+1)-7 equation:


Simplifying
2(c + 2) = 5(x + 1) + -7

Reorder the terms:
2(2 + c) = 5(x + 1) + -7
(2 * 2 + c * 2) = 5(x + 1) + -7
(4 + 2c) = 5(x + 1) + -7

Reorder the terms:
4 + 2c = 5(1 + x) + -7
4 + 2c = (1 * 5 + x * 5) + -7
4 + 2c = (5 + 5x) + -7

Reorder the terms:
4 + 2c = 5 + -7 + 5x

Combine like terms: 5 + -7 = -2
4 + 2c = -2 + 5x

Solving
4 + 2c = -2 + 5x

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + 2c = -2 + -4 + 5x

Combine like terms: 4 + -4 = 0
0 + 2c = -2 + -4 + 5x
2c = -2 + -4 + 5x

Combine like terms: -2 + -4 = -6
2c = -6 + 5x

Divide each side by '2'.
c = -3 + 2.5x

Simplifying
c = -3 + 2.5x

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