2(c+3)-5=6c-2(1+2c)

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Solution for 2(c+3)-5=6c-2(1+2c) equation:


Simplifying
2(c + 3) + -5 = 6c + -2(1 + 2c)

Reorder the terms:
2(3 + c) + -5 = 6c + -2(1 + 2c)
(3 * 2 + c * 2) + -5 = 6c + -2(1 + 2c)
(6 + 2c) + -5 = 6c + -2(1 + 2c)

Reorder the terms:
6 + -5 + 2c = 6c + -2(1 + 2c)

Combine like terms: 6 + -5 = 1
1 + 2c = 6c + -2(1 + 2c)
1 + 2c = 6c + (1 * -2 + 2c * -2)
1 + 2c = 6c + (-2 + -4c)

Reorder the terms:
1 + 2c = -2 + 6c + -4c

Combine like terms: 6c + -4c = 2c
1 + 2c = -2 + 2c

Add '-2c' to each side of the equation.
1 + 2c + -2c = -2 + 2c + -2c

Combine like terms: 2c + -2c = 0
1 + 0 = -2 + 2c + -2c
1 = -2 + 2c + -2c

Combine like terms: 2c + -2c = 0
1 = -2 + 0
1 = -2

Solving
1 = -2

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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