2(c+3)=4c+18

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Solution for 2(c+3)=4c+18 equation: 



2(c+3)=4c+18

We move all terms to the left:

2(c+3)-(4c+18)=0

We multiply parentheses

2c-(4c+18)+6=0

We get rid of parentheses

2c-4c-18+6=0

We add all the numbers together, and all the variables

-2c-12=0

We move all terms containing c to the left, all other terms to the right

-2c=12

c=12/-2

c=-6

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