2(c+3)=5(c-3)

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Solution for 2(c+3)=5(c-3) equation: 



2(c+3)=5(c-3)

We move all terms to the left:

2(c+3)-(5(c-3))=0

We multiply parentheses

2c-(5(c-3))+6=0



We calculate terms in parentheses: -(5(c-3)), so:

5(c-3)

We multiply parentheses

5c-15

Back to the equation:

-(5c-15)



We get rid of parentheses

2c-5c+15+6=0

We add all the numbers together, and all the variables

-3c+21=0

We move all terms containing c to the left, all other terms to the right

-3c=-21

c=-21/-3

c=+7

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