2(c+3)=c-6

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Solution for 2(c+3)=c-6 equation: 



2(c+3)=c-6

We move all terms to the left:

2(c+3)-(c-6)=0

We multiply parentheses

2c-(c-6)+6=0

We get rid of parentheses

2c-c+6+6=0

We add all the numbers together, and all the variables

c+12=0

We move all terms containing c to the left, all other terms to the right

c=-12

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