2(c+4)+3c=5(2c+10)

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Solution for 2(c+4)+3c=5(2c+10) equation:


Simplifying
2(c + 4) + 3c = 5(2c + 10)

Reorder the terms:
2(4 + c) + 3c = 5(2c + 10)
(4 * 2 + c * 2) + 3c = 5(2c + 10)
(8 + 2c) + 3c = 5(2c + 10)

Combine like terms: 2c + 3c = 5c
8 + 5c = 5(2c + 10)

Reorder the terms:
8 + 5c = 5(10 + 2c)
8 + 5c = (10 * 5 + 2c * 5)
8 + 5c = (50 + 10c)

Solving
8 + 5c = 50 + 10c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-10c' to each side of the equation.
8 + 5c + -10c = 50 + 10c + -10c

Combine like terms: 5c + -10c = -5c
8 + -5c = 50 + 10c + -10c

Combine like terms: 10c + -10c = 0
8 + -5c = 50 + 0
8 + -5c = 50

Add '-8' to each side of the equation.
8 + -8 + -5c = 50 + -8

Combine like terms: 8 + -8 = 0
0 + -5c = 50 + -8
-5c = 50 + -8

Combine like terms: 50 + -8 = 42
-5c = 42

Divide each side by '-5'.
c = -8.4

Simplifying
c = -8.4

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