2(c+4)-7=11

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Solution for 2(c+4)-7=11 equation: 



2(c+4)-7=11

We move all terms to the left:

2(c+4)-7-(11)=0

We add all the numbers together, and all the variables

2(c+4)-18=0

We multiply parentheses

2c+8-18=0

We add all the numbers together, and all the variables

2c-10=0

We move all terms containing c to the left, all other terms to the right

2c=10

c=10/2

c=5

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