2(c+4)=5(c+1)-7

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Solution for 2(c+4)=5(c+1)-7 equation: 



2(c+4)=5(c+1)-7

We move all terms to the left:

2(c+4)-(5(c+1)-7)=0

We multiply parentheses

2c-(5(c+1)-7)+8=0



We calculate terms in parentheses: -(5(c+1)-7), so:

5(c+1)-7

We multiply parentheses

5c+5-7

We add all the numbers together, and all the variables

5c-2

Back to the equation:

-(5c-2)



We get rid of parentheses

2c-5c+2+8=0

We add all the numbers together, and all the variables

-3c+10=0

We move all terms containing c to the left, all other terms to the right

-3c=-10

c=-10/-3

c=3+1/3

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