2(c+5)+5(3c-2)=

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Solution for 2(c+5)+5(3c-2)= equation:


Simplifying
2(c + 5) + 5(3c + -2) = 0

Reorder the terms:
2(5 + c) + 5(3c + -2) = 0
(5 * 2 + c * 2) + 5(3c + -2) = 0
(10 + 2c) + 5(3c + -2) = 0

Reorder the terms:
10 + 2c + 5(-2 + 3c) = 0
10 + 2c + (-2 * 5 + 3c * 5) = 0
10 + 2c + (-10 + 15c) = 0

Reorder the terms:
10 + -10 + 2c + 15c = 0

Combine like terms: 10 + -10 = 0
0 + 2c + 15c = 0
2c + 15c = 0

Combine like terms: 2c + 15c = 17c
17c = 0

Solving
17c = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Divide each side by '17'.
c = 0

Simplifying
c = 0

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