2(c+5)-7=3(c-2)

Solution for 2(c+5)-7=3(c-2) equation:

2(c+5)-7=3(c-2)

We move all terms to the left:

2(c+5)-7-(3(c-2))=0

We multiply parentheses

2c-(3(c-2))+10-7=0


We calculate terms in parentheses: -(3(c-2)), so:

3(c-2)

We multiply parentheses

3c-6

Back to the equation:

-(3c-6)


We add all the numbers together, and all the variables

2c-(3c-6)+3=0

We get rid of parentheses

2c-3c+6+3=0

We add all the numbers together, and all the variables

-1c+9=0

We move all terms containing c to the left, all other terms to the right

-c=-9

c=-9/-1

c=+9