2(c+5)=3(2c+2)

Solution for 2(c+5)=3(2c+2) equation:

Simplifying
2(c + 5) = 3(2c + 2)

Reorder the terms:
2(5 + c) = 3(2c + 2)
(5 * 2 + c * 2) = 3(2c + 2)
(10 + 2c) = 3(2c + 2)

Reorder the terms:
10 + 2c = 3(2 + 2c)
10 + 2c = (2 * 3 + 2c * 3)
10 + 2c = (6 + 6c)

Solving
10 + 2c = 6 + 6c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-6c' to each side of the equation.
10 + 2c + -6c = 6 + 6c + -6c

Combine like terms: 2c + -6c = -4c
10 + -4c = 6 + 6c + -6c

Combine like terms: 6c + -6c = 0
10 + -4c = 6 + 0
10 + -4c = 6

Add '-10' to each side of the equation.
10 + -10 + -4c = 6 + -10

Combine like terms: 10 + -10 = 0
0 + -4c = 6 + -10
-4c = 6 + -10

Combine like terms: 6 + -10 = -4
-4c = -4

Divide each side by '-4'.
c = 1

Simplifying
c = 1