2(c+6)=5+3(c-1)

Solution for 2(c+6)=5+3(c-1) equation:

2(c+6)=5+3(c-1)

We move all terms to the left:

2(c+6)-(5+3(c-1))=0

We multiply parentheses

2c-(5+3(c-1))+12=0


We calculate terms in parentheses: -(5+3(c-1)), so:

5+3(c-1)

determiningTheFunctionDomain
3(c-1)+5

We multiply parentheses

3c-3+5

We add all the numbers together, and all the variables

3c+2

Back to the equation:

-(3c+2)


We get rid of parentheses

2c-3c-2+12=0

We add all the numbers together, and all the variables

-1c+10=0

We move all terms containing c to the left, all other terms to the right

-c=-10

c=-10/-1

c=+10