2(c+8)=2(2c+1)

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Solution for 2(c+8)=2(2c+1) equation: 



2(c+8)=2(2c+1)

We move all terms to the left:

2(c+8)-(2(2c+1))=0

We multiply parentheses

2c-(2(2c+1))+16=0



We calculate terms in parentheses: -(2(2c+1)), so:

2(2c+1)

We multiply parentheses

4c+2

Back to the equation:

-(4c+2)



We get rid of parentheses

2c-4c-2+16=0

We add all the numbers together, and all the variables

-2c+14=0

We move all terms containing c to the left, all other terms to the right

-2c=-14

c=-14/-2

c=+7

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