2(c+y)+3(b+c)=

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Solution for 2(c+y)+3(b+c)= equation:


Simplifying
2(c + y) + 3(b + c) = 0
(c * 2 + y * 2) + 3(b + c) = 0
(2c + 2y) + 3(b + c) = 0
2c + 2y + (b * 3 + c * 3) = 0
2c + 2y + (3b + 3c) = 0

Reorder the terms:
3b + 2c + 3c + 2y = 0

Combine like terms: 2c + 3c = 5c
3b + 5c + 2y = 0

Solving
3b + 5c + 2y = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-5c' to each side of the equation.
3b + 5c + -5c + 2y = 0 + -5c

Combine like terms: 5c + -5c = 0
3b + 0 + 2y = 0 + -5c
3b + 2y = 0 + -5c
Remove the zero:
3b + 2y = -5c

Add '-2y' to each side of the equation.
3b + 2y + -2y = -5c + -2y

Combine like terms: 2y + -2y = 0
3b + 0 = -5c + -2y
3b = -5c + -2y

Divide each side by '3'.
b = -1.666666667c + -0.6666666667y

Simplifying
b = -1.666666667c + -0.6666666667y

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