2(c-1)-6c=10-2(c-4)

Solution for 2(c-1)-6c=10-2(c-4) equation:

2(c-1)-6c=10-2(c-4)

We move all terms to the left:

2(c-1)-6c-(10-2(c-4))=0

We add all the numbers together, and all the variables

-6c+2(c-1)-(10-2(c-4))=0

We multiply parentheses

-6c+2c-(10-2(c-4))-2=0


We calculate terms in parentheses: -(10-2(c-4)), so:

10-2(c-4)

determiningTheFunctionDomain
-2(c-4)+10

We multiply parentheses

-2c+8+10

We add all the numbers together, and all the variables

-2c+18

Back to the equation:

-(-2c+18)


We add all the numbers together, and all the variables

-4c-(-2c+18)-2=0

We get rid of parentheses

-4c+2c-18-2=0

We add all the numbers together, and all the variables

-2c-20=0

We move all terms containing c to the left, all other terms to the right

-2c=20

c=20/-2

c=-10