2(c-3)+2c=2(10-c)

Solution for 2(c-3)+2c=2(10-c) equation:

Simplifying
2(c + -3) + 2c = 2(10 + -1c)

Reorder the terms:
2(-3 + c) + 2c = 2(10 + -1c)
(-3 * 2 + c * 2) + 2c = 2(10 + -1c)
(-6 + 2c) + 2c = 2(10 + -1c)

Combine like terms: 2c + 2c = 4c
-6 + 4c = 2(10 + -1c)
-6 + 4c = (10 * 2 + -1c * 2)
-6 + 4c = (20 + -2c)

Solving
-6 + 4c = 20 + -2c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '2c' to each side of the equation.
-6 + 4c + 2c = 20 + -2c + 2c

Combine like terms: 4c + 2c = 6c
-6 + 6c = 20 + -2c + 2c

Combine like terms: -2c + 2c = 0
-6 + 6c = 20 + 0
-6 + 6c = 20

Add '6' to each side of the equation.
-6 + 6 + 6c = 20 + 6

Combine like terms: -6 + 6 = 0
0 + 6c = 20 + 6
6c = 20 + 6

Combine like terms: 20 + 6 = 26
6c = 26

Divide each side by '6'.
c = 4.333333333

Simplifying
c = 4.333333333